Research website of Vyacheslav Gorchilin
2019-04-13
Unsupported mover on uncompensated charge. Condenser principle. Earlier it was proposed a magnetic version of the mover on an uncompensated charge. Here we will consider its capacitor and the propulsion on this basis. In fact, the principle is the same everywhere — it is important to make the charges move with different speed, then between them there are additional uncompensated forces. . In this case, the charge \ on the surface of the conductor w2 is stationary and moving charge \ to the conductor w1 with the speed \ . Since the conductors are interconnected mechanically linked, such that the Coulomb forces are mutually compensated, but there is a Lorentz force \, which is directed perpendicular to as the magnetic induction vector \ and the vector of its velocity \ . This force would be uncompensated and would represent the thrust of the propeller . . . The Lorentz force is determined in the classical way: $F = q_2 B_1 \vartheta_1 \qquad$ it includes the charge on the surface of the conductor w2, which, however, may be with the conductor w1 capacity \. Then this charge will be simple: $q_2 = C_2 U_2 \qquad$ the Magnetic induction we can take from the formula for an infinite conductor, and if necessary a more accurate calculation, it can be replaced at any time. But for clarity, while we consider an idealized model: $B_1 = {\mu\mu_0 I_1 \over 2\pi r} \qquad$ Here \ — distance between conductors. It must be greater than the average radius w1. \ — relative and absolute magnetic permeability. . Now we got a movement speed of the magnetic induction vector. It affects almost all the power, so it is important that this speed was how can more . Suppose that in our construction, as w1, we apply a vacuum lamp in which, between the cathode and the anode will accelerate the electrons to high velocities. From the classics it is known that in this case, the average velocity of the charges in the lamp can be calculated by the following formula: $\vartheta_1 = 3\cdot 10^5 \sqrt{U_1} \qquad$ Substituting all these expressions into yields the final formula for finding the thrust force of the engine is: $F = 3\cdot 10^5\, {\mu\mu_0 \over 2\pi r}\, I_1 C_2 U_2 \sqrt{U_1} \qquad$ Recall that all the formulas here are given in the international system of units SI. .  . 1 2 . .