Research website of Vyacheslav Gorchilin
2021-10-21
All articles/Planet Earth
Connection of the Earth's orbit with the number of free electrons in its volume
"Unity in diversity is most easily grasped by analogy. For - as above, so below, so everywhere and in everything. … The law of analogy reigns in the world". Facets of Agni Yoga. 1966:121
This is a very unusual idea that, in the future, may open up a new direction in science - wave electricity. Its meaning is very simple: everything consists of waves, while matter is secondary, and is felt by us as a result of their interaction. In this work, the wave connection of free electrons of the planet with the radius of the orbit around its star will be shown, but with the further assumption that the same strategy can be extended to the microcosm. The work became possible thanks to many years of research, links to which will appear as you read it.
We will approach this issue from the perspective of the planet Earth, as a point object orbiting a "star called the Sun" (another point object). Also, we will choose the average radius of the Earth's orbit, equal to 150 million kilometers [1] and we will consider the Earth from the point of view of electrodynamics. These initial conditions are necessary to get away from the classical model of planet rotation, although we will return to it a little later for comparison and optimization.
In fact, the planet moves around the star in an elliptical orbit, the eccentricity of which is not taken into account in this work, which is inherently more qualitative than quantitative. However, the eccentricity of the Earth is only 0.017 [2].
Schematic rotation of the Earth around the Sun
Fig.1. Schematic rotation of the Earth around the Sun
We already know that an electron, from the point of view of radio electronics and electrodynamics, is an ideal oscillatory circuit. Let's consider our planet from the same point of view, and imagine it as an oscillating circuit with distributed parameters of current and voltage. As a basis, we can take the analogy with a Tesla coil, at both ends of which there are the same zero potentials, which is possible when the coil operates in half-wave mode . In other words, oscillations of the 2nd harmonic must be applied to the Tesla coil, counting from the fundamental resonant frequency. We already know that the fundamental resonance frequency of such a coil is according to the classic Thompson formula: \[f_ {1} = {1 \over 2 \pi \sqrt {L_p C_p}} \qquad (1.1) \] and its second harmonic will be calculated as follows: \[f_ {p} = f_ {2} = \left ({i + 2 \over 2} \right) f_ {1} = 2 f_ {1} \qquad (1.2) \] Calculation of harmonics can be taken from of this work. In these formulas: \(L_p \) is the inductance, and \(C_p \) is the capacity of all the electrons of the planet, \(i \) is the harmonic number, which in this case is equal to 2, a \(f_p \) is the resonant frequency of the planet, formed by its free electrons.
Now let's find this inductance and capacitance. The inductance of all free electrons of the Earth will be found, obviously, as the sum of all the intrinsic inductances of each electron: \[L_ {p} = N_p \, L_e \qquad (1.3) \] It can be considered as series-connected elementary inductances, the number of which is \(N_p \), and it is equal to the number of free electrons of the planet. It should be recalled here that self-inductance of one electron is equal to: \[L_e = 2.82 \cdot 10 ^ {- 22} \, (H) \qquad \] The total intrinsic capacity of all free electrons of the planet will also be found by summing up the intrinsic capacities of each electron: \[C_p = N_p \, C_e \qquad (1.4) \] It can be considered as parallel connected elementary capacities. Let's remind that own capacity of one electron is equal to: \[C_e = 3.14 \cdot 10^{-25} \, (F) \qquad \]
In this problem, one number appeared, which determines all further calculations and on which all output parameters depend, this is the number of free electrons in the Earth. It can be found as the total charge of the planet divided by the elementary charge of an electron [3]. The electrical charge of the Earth was experimentally found here and differs from the educational one several times. Now you can find the number of free electrons in the Earth: \[N_p = {q_E \over q_e} = 1.94 \cdot 10 ^ {25} \qquad (1.5) \] Let's remember this number, it will be useful to us in all further calculations. For example, from here you can calculate the total inductance of all free electrons of the Earth: \[L_ {p} = 5.47 \cdot 10 ^ {3} \, (H) \qquad \] Substituting expressions (1.3-1.4) into formula (1.1), we find the resonant frequency of the planet (according to Thompson), formed by its free electrons: \[f_ {p} = {1 \over \pi N_E \sqrt {L_e C_e}} \qquad (1.6) \] Considering that the speed of propagation of the wave formed by this huge oscillatory circuit in vacuum is equal to the speed of light, then we can find half of its length (recall that we consider the half-wave mode): \[\lambda_p / 2 = \pi c N_p \sqrt {L_e C_e} \qquad (1.7) \] If we finally calculate the wavelength of planet Earth, then it will be approximately equal to \(R_E \) - the radius of its orbit around the Sun: \[R_E \approx \lambda_p / 2 = 1.7 \cdot 10 ^ {11} \, (m) \qquad \] The error of the obtained data with astronomical data is 15% and it is most likely associated with not very precise conditions for determining the the planet's charge. The error is also influenced by our simplification about its lack of eccentricity.
Interestingly, the result obtained can be completely simplified if we apply known data about the electron: \[R_E = \pi r_e N_p \qquad (1.8) \] or: \[\lambda_p = \lambda_e N_p \qquad (1.9) \] Here: \(r_e \) is the radius of the electron, \(\lambda_e \) is the wavelength of the electron (according to Thompson).
Thus, it turns out that the wavelength of the planet is equal to the sum of the wavelengths of all free electrons in its volume.
Optimal Orbit
Let's look at the planet's orbit from a classical point of view. Its radius is found as a condition for balancing the centrifugal repulsive force and the gravitational force of attraction. The first depends on the speed of rotation of the planet around the star, and the second depends on the mass of the planet and the star, and the distance between them. This distance is the radius of the orbit. Thus, the radius of rotation of the planet around the star can be, theoretically, any: increase the rotation speed of the planet, the radius of its orbit will increase, and vice versa.
But is there an optimal orbit for a particular planet? Apparently, yes, and the radius of such an orbit depends on the number of free electrons in the volume of this planet. The planet strives to occupy a position at the nodes of a standing wave [4] formed by its distributed oscillatory circuit. You can find this optimal radius by the formulas (1.7-1.8).
Optimal orbit of the planet when it takes its place in the nodes of the standing wave
Fig.2. Optimal orbit of the planet when it takes its place in the nodes of the standing wave
Schematically, the distribution of the wave between the planet and its star is shown in Figure 2. It can be assumed that the planet can be located at any node: 1, 2, 3, 4, etc.
Conclusions
From this work, we can conclude that the solar, and apparently any other planetary system, is a finely tuned organism that resembles a musical instrument. The planets of this system are located exactly in the nodes of the planetary waves in relation to the star, and possibly in the wave nodes generated by the star itself.
In this work, we studied planetary waves formed by free electrons in the volume of the planet. These studies have shown that the planet, relative to its star, is located at the nodes of such a wave (Fig. 2). Apparently, wave nodes have certain physical properties, akin to gravitational ones, which have yet to be studied by science.
It also showed the calculated data relating directly to the Earth, which is also located at the node of the wave formed by the free electrons of this planet. The same calculations can show and, most importantly, explain at least three Lagrange points: L3, L4, L5. The points L1 and L2 are apparently related to the eccentricity of our planet's orbit [5].
The formulas obtained may also apply to the microcosm, for example, to a system formed by several free electrons (1.9). It follows from the formulas that the wavelength of such a system is equal to the sum of the wavelengths of all free electrons in its volume, and the center of its rotation is located at the node of such a wave.
The materials used
  1. Wikipedia. Earth.
  2. Wikipedia. Orbit eccentricity.
  3. Wikipedia. Elementary electric charge.
  4. Wikipedia. Thickness and the knot of a standing wave.
  5. Wikipedia. Lagrange Points.